an object is placed at a distance 50 cm from a convex lense of focal length 60 cm.find the image distance and magnification
Answers
Answered by
1
Explanation:
u=−60cm
u
−v
=
2
1
⇒
−60
−v
=
2
1
⇒v=30cm
⇒
v
1
+
u
1
=
f
1
⇒
f
1
=
30
1
+
−60
1
⇒
f
1
=
60
2−1
=
60
1
⇒f=60cm
Now magnification=
3
1
u
−v
=
3
1
⇒v=
3
−u
∴
v
1
+
u
1
=
f
1
⇒
3
−u
1
+
u
1
=
f
1
⇒
u
−3
+
u
1
=
60
1
⇒
u
−2
=
60
1
⇒u=−120cm
Answered by
1
f=60 cm,u=-50 cm ,v=?
By lens formula we have,
(1/f)=(1/v)-(1/u)
1/60=1/v-(1/-50)
1/60=(1/v)+(1/50)
1/v=(1/60)-(1/50)
1/v=(5-6)/300
1/v=-1/300
v=-300 cm
So the image distance is 300 cm away
Magnification(m)=v/u
=-300/-50
=6
By lens formula we have,
(1/f)=(1/v)-(1/u)
1/60=1/v-(1/-50)
1/60=(1/v)+(1/50)
1/v=(1/60)-(1/50)
1/v=(5-6)/300
1/v=-1/300
v=-300 cm
So the image distance is 300 cm away
Magnification(m)=v/u
=-300/-50
=6
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