Question

An object is placed at a distance of 10 cm a convex mirror of a focal length 15 cm .find the Postion and nature of image.
​

Answer 1

$\underline{ \pink{\frak{ \: \: \: \: Solution : \: \: \: \: }}}$

• Focal length = 15 cm
• Distance of object = 20 cm
• Type of mirror = convex mirror

According to Question now :-

Using Mirror formula :-

As we know the mirror formula ,

1/f = 1/v + 1/u

Here,

f = Focal Length

u = Distance of object

v = Distance of image

$\dashrightarrow\:\:\sf \dfrac{1}{15} = \dfrac{1}{v} + \dfrac{1}{( - 10)}$

$\dashrightarrow\:\:\sf \dfrac{1}{v} = \dfrac{1}{15} + \dfrac{1}{10}$

$\dashrightarrow\:\:\sf \dfrac{1}{v} = \dfrac{10 + 15}{150}$

$\dashrightarrow\:\:\sf \dfrac{1}{v} = \dfrac{25}{150}$

$\dashrightarrow\:\:\sf v = \dfrac{1}{6}$

$\dashrightarrow\:\:\underline{\boxed{\sf v = \dfrac{1}{6} \: cm}}$

v = 6 cm {Image Distance}

⠀━━━━━━━━━━━━━━━━━━━━━━━━━

$\large\bigstar\:\underline{\textsf{Nature of image, Size of image and Position of image :}}$

$\bullet\:\:\textsf{Position of image = \textbf{Backside of the mirror}}$

$\bullet\:\:\textsf{Nature of image = \textbf{virtual and erect}}$

══════════════════════════

Note :-

App User?

Swipe left to see whole answer !