Question

Intensity of current in the secondary coil
of a transformer is 1A and that of
Primary is 5A. If there is 100 v
in secondary find voltage in
the primary​

Answer 1

Correct Question:

Intensity of current in the secondary coil  of a transformer is 1A and that of  Primary coil is 5A. If there is 100 Volts  in secondary coil, Find the voltage in  the primary​ coil?

Answer:

• The voltage in primary coil is 20 volts

Explanation:

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Given, we have intensity of current in secondary and primary coil is 1A and 5A respectively. and, the voltage is given in secondary coil and we need to find the voltage in primary coil. From the formula we know that,

⇒ Vₚ Iₚ = Vₛ Iₛ

Here,

• Vₚ Denotes voltage in Primary coil.
• Iₚ Denotes current in Primary coil.
• Vₛ Denotes voltage in Secondary coil.
• Iₛ Denotes current in Secondary coil.

Substituting the values,

⇒ Vₚ × 5 = 100 × 1

⇒ 5 Vₚ = 100

⇒ Vₚ = 100/5

⇒ Vₚ = 20

⇒ Vₚ = 20 volts

∴ The voltage in primary coil is 20 volts.

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Answer 2

Answer:

The intensity of current in the secondary coil  of a transformer is 1A and that of  the primary is 5A. If there is 100 v  in secondary the voltage in  the primary​ coil is 20v

​Explanation:

• In a transformer, there is a primary coil with a number of turns $N_{1}$ voltage, and current through it is $I_{1}$. In the secondary coil, the number of turns is $N_{2}$ voltage is $V_{2}$ and current is $I_{2}$

• The relation connecting these parameters is given by the formula

        $\frac{N_{1} }{N_{2} } =\frac{V_{1} }{V_{2} }=\frac{I_{2} }{I_{1} }$

From the question, we have

current in the primary coil $I_{1} =5A$

current in the secondary coil $I_{2} =1A$

the ratio of currents  $I_{1} /I_{2} =5$

the voltage in the secondary coil is $V_{2} =100v$

the voltage in the primary coil $V_{1} =\frac{I_{2} }{I_{1} } V_{2}$

⇒$V_{1} =100/5=20v$