Question

an object is placed at a distance of 10 cm from a concave mirror of focal length 5cm. Find the position, nature and size of the image formed? ​

Answer 1

The solution is given below

Answer 2

Given:

• Object distance = 10 cm
• Focal length = 5cm
• Mirror is concave

To find:

Image distance & nature of image ?

Calculation:

Applying MIRROR FORMULA (with sign conventions):

$\dfrac{1}{f} = \dfrac{1}{v} + \dfrac{1}{u}$

$\implies \dfrac{1}{ - 5} = \dfrac{1}{v} + \dfrac{1}{ - 10}$

$\implies - \dfrac{1}{ 5} = \dfrac{1}{v} - \dfrac{1}{ 10}$

$\implies \dfrac{1}{v} = \dfrac{1}{ 10} - \dfrac{1}{5}$

$\implies \dfrac{1}{v} = \dfrac{1 - 2}{ 10}$

$\implies \dfrac{1}{v} = \dfrac{ - 1}{ 10}$

$\implies \: v = - 10 \: cm$

So, image is located 10 cm in front of mirror.

Now, image is :

• Real, inverted and equal in size as that of the object.

• Image is formed at the centre of curvature of the mirror.

Hope It Helps.