Question

An object is placed at a distance of 10 cm from a convex mirror of focal length 5 cm.
(i) Draw a ray-diagram showing the formation image
(ii) State two characteristics of the image formed
(iii) Calculate the distance of the image from mirror.

Answer 1

Explanation:

Object distance, u = 10 cm.

Focal length, f = 5 cm.

(i) Ray diagram is shown below:

Two characteristics of the image formed are:

   1) Virtual

  2) Diminished as well as erect.

We have to calculate image distance i.e., v.

According to the mirror formula,

$\frac{1}{(Focal length)} = \frac{1}{(object distance)} +\frac{1}{(image distance)}$

I.e., $\frac{1}{f} = \frac{1}{u} +\frac{1}{v}$

i.e., $\frac{1}{v} = \frac{1}{f} - \frac{1}{u}$

i.e.,  $\frac{1}{v} = \frac{1}{5} -\frac{-1}{-10} = \frac{1}{5} +\frac{1}{10} = \frac{(2+1)}{10} =\frac{3}{10}$

i.e., $v = \frac{10}{3} = 3.3 cm.$

Therefore, the distance of the image from the mirror is 3.3 cm.

You can get all the answers of Chapter 4 in the link below:

https://brainly.in/question/14963178

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