An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm . Find the position and nature of the image
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GIVEN:
Image distance (u)=-10 cm
focal length (f)=15 cm
SOLUTION:
1/f=1/v+1/u
1/v=1/f- 1/u
1/v=1/15-(- 1/10)
1/v=25/150
v=150/25
v=6 cm
object is formed behind the mirror
m= -v/u= -6/-10=0.6
The image formed is virtual erect and small
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