Question

An object is placed at a distance of 10cm from a diverging mirror of focal length 15cm.Find the position and nature of the image formed .Also, calculate the magnification of the image.​

Answer 1

Answer:

-30 cm

Explanation:

1/f=1/v+1/u

f=15

u=-10

1/15=1/v+1/-10

1/15-(-1/10)=1/v

-10+15/-150=1/v

v=-150/5

v=-30cm

Answer 2

Answer:

using sign convention

u=-10 cm

f=15cm

v=?

1/f=1/v+1/u

1/15=1/v- 1/10

1/15+1/10=1/v

1/v=2+3/30

1/v=1/6

v=6cm

since vis positive.

so image is virtual