an object is placed at a distance of 10cm in front of a concave mirror and its erect and magnified image is formed at a distance of 30cm from the mirror. What is the focal length of the mirror.
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Explanation:
Soln :-. Given u = -10cm , v= ? , f = -15cm
Applying mirror's formula,1/v +1/u = 1/f
1/v + 1/-10 = 1/-15
1/v = -1/15 + 1/10
=(-2+3)/30
= 1/30
V = 30 cm.
Hence, we get enlarged image, virtual in nature having magnification 3.
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