Question

an object is placed at a distance of 15 cm from a convex mirror of focal length 30 cm find the position and nature of the image

Answer 1

u = - 15 cm, f = 30 cm

1/f = 1/v + 1/u  

1/v = 1/f - 1/u = 1/30 + 1/15 = 1/10

v = 10 cm.

magnification m = - v/u = - 10 / - 15 =  0.67

nature of image is virtual, diminish and erect

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