Question

an object is placed at a distance of 15 cm from a diverging mirror of focal length 6 cm find the nature and position of object.​

Answer 1

Answer:

I hope this answer is helpful

Answer 2

Answer:

We know that if u= object distance, v= image distance and f= focal length of convex mirror,

1/v + 1/u= 1/f

⇒ 1/v= 1/f- 1/u

⇒ 1/v= 1/6-(- 1/15) ( following the sign convention for diverging mirror )

⇒ 1/v = 1/ 6 + 1/ 15

⇒ 1/v= 7/ 30

⇒ v= 30/7 cm

Magnification (m) = -v/u = 2/7 ( again check sign convention )

Therefore the object will be placed to the left of the convex lens and the image will be formed to the right. It is virtual, erect and smaller in size than the object.

Below I have attached the sign conventions for further requirement. Hope this helps.