an object is placed at a distance of 15 cm from the following mirrors, of focal length 10 cm , find the position nature of image
concave mirror and convex mirror
Answers
Answered by
2
first we'll take the case of concave mirror..
the mirror formula is.......1/f = 1/v + 1/u.
in our case u = -15cm
f = -10cm
therefore 1/-10 = 1/-15 + 1/v
1/v = 1/-10 + 1/15
v = -30
magnification formula is -v/u
.....................30/-15
the object is magnified with a factor of -2
the image formed is real inverted, magnified.
thanks for watching
the mirror formula is.......1/f = 1/v + 1/u.
in our case u = -15cm
f = -10cm
therefore 1/-10 = 1/-15 + 1/v
1/v = 1/-10 + 1/15
v = -30
magnification formula is -v/u
.....................30/-15
the object is magnified with a factor of -2
the image formed is real inverted, magnified.
thanks for watching
Answered by
2
Answer:
+ 6 cm
Explanation:
Given :
Object distance = - 10 cm
Focal length = + 15 cm
We have to find image distance.
We know :
1 / f = 1 / v + 1 / u
1 / v = 1 / f - 1 / u
1 / v = 1 / 15 + 1 / 10
1 / v = 1 / 6
v = + 6 cm
Hence .image distance is 6 cm from the mirror behind it.
The image is erect and virtual.
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