Question

An object is placed at a distance of 15cm from a convex lens of focal length 10cm. Find the position and nature of image formed.

Answer 1

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Answer 2

The image is located at a distance of 30 cm from the lens and the formed image is virtual and erect.

Explanation:

Given that,

Object distance from a lens, u = -15 cm

Focal length of the convex lens, f = +10 cm

Using lens formula to find the image distance as :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}\\\\\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{10}+\dfrac{1}{(-15)}\\\\v=30\ cm$

The image is located at a distance of 30 cm from the lens.

The ratio of image distance to the object distance is called magnification. So,

$m=\dfrac{-v}{u}\\\\m=\dfrac{-30}{-15}\\\\m=2$

It shows the formed image is virtual and erect.

Learn more,

Lens formula

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