Question

An object is placed at a distance of 30 cm from a convex mirror, the magnification produced is 1/2. Where should the ohect be placed to get a magnificationof 1/3

Answer 1

Answer:

v = 15 cm

f =30cm

Explanation:

it can be done by using magnification and mirror formula

Answer 2

Answer:

The object should be placed 60 cm from the convex mirror to get a magnification of 1/3.

Explanation:

From the above question,

They have given :

u1 = −30 cm

m = 12

The formula of magnification is given as

  m= − $\frac{v1}{u1}$

The reflect method is:

                1/f = 1/v + 1/u

                m = -v/u

where m is the magnification. Substituting the given values, we get:

              $\frac{1}{2}$ = - $\frac{V}{30}$

              v = -15 cm

The bad signal suggests that the photograph is digital and upright.

The magnification in this case is given as:

       m' = -v'/u' = 1/3

We choose to locate the new object distance u'. We can rearrange the magnification components to resolve for v':

                    v' = -m'u'

Substituting the values, we get:

                    -15 cm = - (1/3) v'

                    v' = forty five cm

Now, we can use the replicate method to locate the object distance u':

                    1/f = 1/v' + 1/u'

Substituting the values, we get:

                    1/f = 1/45 + 1/u'

Let's anticipate that the focal size of the replicate is f. We can rearrange the equation to resolve for u':

                    $\frac{1}{u^{'} }$  = 1/f - 1/45

                    u' = 45f / (46 - f)

Now we can alternative the price of the magnification and resolve for the object distance u:

                   1/3 = - $\frac{v^{'} }{u^{'} }$  = -45 / (u' f)

Substituting the cost of u' and simplifying, we get:

                 1/3 = -45 / (f (45f / (46 - f)))

                    f = 60 cm

Therefore, the required focal size of the convex replicate is 60 cm. To locate the new object distance u', we can alternative this price into the equation we derived earlier:

                u' = 45f / (46 - f)

                u' = 450 cm / 7

Therefore, the object have to be positioned at a distance of about 60 cm from the convex replicate to acquire a magnification of 1/3.

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