Question

if A and B are angles of a right angled ABC , right angled at C prove that sin2A+sin2B=1

Answer 1

☆☆ranshsangwan☆☆

Triangle ABC is right angled at C.

So C=90

A+B+C=180

A+B+90=180

A+B=180-90=90

B=90-A

So 


=sin^2A+sin^2B
= sin^2A+sin^2(90+A)

= sin^2A+cos^A
= 1