Question

An object is placed at a distance of 30cm from a concave lens of focal length 15cm. Find position and nature of image

Answer 1

Object Distance= -30
Focal Length= -15

Lens formula =>         1/v -1/u = 1/f
                 1/v+1/30= -1/15
                  1/v= -3/30
                    v= -30/3
                     v= -10
the image formed is thus Virtual and Erect 
and is formed behind the lens