Question

An object is placed at a distance of 50 cm from a concave lens of focal length 20 cm. Find the nature and position of the image. Also find the magnification of the lens.

Answer 1

https://brainly.in/question/4513352
Please follow the same procedure present on this link

Answer 2

Explanation:

The nature and approximate position is trivial. Concave lenses always produce virtual, upright, reduced images closer to the lens than the object.

Use the Lens Formula (here with Real Is Positive convention)

$[1/v + 1/u = 1/f 1/v = 1/f - 1/u][-1/30 - 1/50 = -5/150 - 3/150 = -8/150]$

v = -150/8 or 18.75 from the lens, virtual.

M = v/u = -150/8 / +50 = -3/8

(Negative here indicates erect image)