Question

An object is placed at a distance of 60 cm from a convex mirror where the magnification produced is 1/2 where should the object placed to get a Magnification of 1/3

Answer 1

here's your answer please see the attachment.

Answer 2

$\bold{ANSWER}$

• An object is placed at a $\bold{distance}$ ‘u' =-60cm

•$\bold{magnification}$ produced is 'm'=1/2

$m = \frac{ - v}{u}$

$\frac{1}{2} = \frac{ - v}{ - 60}$

-v = -30cm

v = 30cm

f = ?

☞•$\bold{using \: mirror \: formula}$

$\frac{1}{f} = \frac{ - 1}{60} + \frac{1}{30 }$

☞ f=60 cm

m =1/3

-v/u = 1/ 3

v=(1/3)u

f=60cm

•$\bold{using \: mirror \: formula}$

1/f = 1/u +1/v

1/60= 1/u - 3/u

u =-120cm

☞the object placed at the $\bold{distance}$ of -120cm to get a $\bold{magnification}$ of 1/3.