Question

An object is placed at a distance of 60cm from a convex mirror where the magnification produced is 1/2.Where should the object be placed to get a magnification of 1/3?

Answer 1

m = - v/u
1/2 = - v/-60
v = 30cm
1/v + 1/u = 1/f
1/30 + 1/-60 = 1/f
f = 60cm

m = f/f-u
1/3 = 60/60-u
u = - 120cm