an object is placed at distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image
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Given, u = - 10 cm ; f = 15 cm ; v = ?
1/f = 1/v + 1/u
1/15 = 1/v + 1/-10
1/v = 1/15 + 1/10
1/v = 2+3/30 = 5/30
v = 30/5 = 6 cm
So the image is virtual and seen in the mirror.
1/f = 1/v + 1/u
1/15 = 1/v + 1/-10
1/v = 1/15 + 1/10
1/v = 2+3/30 = 5/30
v = 30/5 = 6 cm
So the image is virtual and seen in the mirror.
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