an object is placed at the distance of 30 cm from a convex mirror magnification produced is 1/2 where should the object placed for the magnification of 1/3
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hii mate !!
Given:
u=-30cm
m=1/2
m=-v/u
1/2=-v/-60
-v=-30cm
v=30cm
f=?
by mirror formula:
-1/60+1/30=1/f
on solving:
f=60cm
m=1/3
1/3=-v/u
v=(1/3)u
f=60cm
using mirror formula:
1/u+1/v=1/f
1/u-3/u=1/60
u=-120cm
hope it helps ☺☺☺☺
Given:
u=-30cm
m=1/2
m=-v/u
1/2=-v/-60
-v=-30cm
v=30cm
f=?
by mirror formula:
-1/60+1/30=1/f
on solving:
f=60cm
m=1/3
1/3=-v/u
v=(1/3)u
f=60cm
using mirror formula:
1/u+1/v=1/f
1/u-3/u=1/60
u=-120cm
hope it helps ☺☺☺☺
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