Question

an object is placed in front of a concave mirror of focal length 15 cm and its inverted sharp image of height 6 cm is observed at the distance of 37.5 from the mirror find the object distance and it's height​

Answer 1

Answer:

object of the distance 37.5 cm

Answer 2

Answer:

The height of object is 9 cm.

Explanation :

Given as :

for concave miorror

focal length = f = 15 cm

distance of image = u = - 37.5 cm

height of image = $h_i$ = 6 cm

Let The height of object = $h_o$  cm

Distance of object = v cm

According to question

From mirror formula

$\dfrac{1}{f}$  = $\dfrac{1}{u}$  +  $\dfrac{1}{v}$

Or, $\dfrac{1}{-15}$ = $\dfrac{1}{-37.5}$ + $\dfrac{1}{v}$

Or, $\dfrac{1}{v}$ = $\dfrac{1}{-15}$  +  $\dfrac{1}{37.5}$

Or, $\dfrac{1}{v}$ = - 0.067 + 0.0267

Or, $\dfrac{1}{v}$  = - 0.0403

Or, v = - 24.8 ≈ - 25

Again

magnification = m = $\dfrac{-v}{u}$  =  $\dfrac{h_i}{h_o}$

Or, $\dfrac{-(-25)}{-37.5}$  =  $\dfrac{6}{h_o}$

Or, - 0.67 = $\dfrac{6}{h_o}$

∴  $h_o$  = - 8.9 cm ≈  - 9 cm

Hence, The height of object is 9 cm. Answer