an object is placed in front of a concave mirror of focal length 20cm three times the size of the object calculate the distance of the object from the mirror
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hello
The mirror formula is
1/f = (1/v) + (1/u) ............. (1)
Given
f = focal length = -20cm
v = image distance
u = object distance
we will assume that the following is given
hi = image height
ho = object height
hi = 3ho
Now,
from formula
hi / ho = -v/u = 3
we get,
v = -3u
so, using this in eq. (1), we get
-1/20 = -1/3u + 1/u
or
-1/20 = 2 / 3u
or
u = -13.33 cm
Thus, the object is distance / position of the object will be
u = -13.33 cm
I hope helps you
thanks for questioning
#be brainly
The mirror formula is
1/f = (1/v) + (1/u) ............. (1)
Given
f = focal length = -20cm
v = image distance
u = object distance
we will assume that the following is given
hi = image height
ho = object height
hi = 3ho
Now,
from formula
hi / ho = -v/u = 3
we get,
v = -3u
so, using this in eq. (1), we get
-1/20 = -1/3u + 1/u
or
-1/20 = 2 / 3u
or
u = -13.33 cm
Thus, the object is distance / position of the object will be
u = -13.33 cm
I hope helps you
thanks for questioning
#be brainly
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