An object is placed perpendicular to the principal axis of concave lens of focal length 30 cm. Find the position of an image when the object is at a distance 20 cm from the lens.Solve the given problem.(Ans: v = -12 cm)
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Focal length(f) = 30 cm. (negative)
Object distance(u) = 20 cm. (negative)
Using the Lens Formula,
1/f = 1/v - 1/u
⇒ 1/-30 = 1/v - 1/-20
⇒ 1/v = 1/-30 + 1/-20
⇒ 1/v = 3/-60
⇒ v = -20 cm.
Hence, the image is formed at the distance of 20 cm on the same side of the lens.
Hope it helps.
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