Question

An object is placed perpendicular to the principle axis of a convex lens of focal length
10cm. The distance of the object from the optic centre of the lens is 15 cm. Calculate
the position of the image formed. Mention the nature of the image.​

Answer 1

Answer:-

v = 30 cm

Given :

u = -15 cm

f = +10 cm

To find :-

The position of the image formed.

Nature of the image .

Solution:-

Let the image formed at v.

By using lens formula,

→$\dfrac{1}{f} = \dfrac{1}{v} - \dfrac{1}{u}$

→$\dfrac{1}{10}= \dfrac{1}{v}-\dfrac{1}{(-15)}$

→$\dfrac{1}{10} = \dfrac{1}{v} + \dfrac{1}{15}$

→$\dfrac{1}{v} = \dfrac{1}{10}-\dfrac{1}{15}$

→$\dfrac{1}{v} = \dfrac{3-2}{30}$

→$\dfrac{1}{v} = \dfrac{1}{30}$

→$v = 30 cm$

Nature → Real and inverted.

Hence,

The Image formed at a distance of 30 cm.