Question

An object is projected at an angle of 45° with the horizontal with kinetic energy K. Its kinetic energy at maximum height is ................ . [K = 1/2 mv²]
(A) 0
(B) K/2
(C) K/â2
(D) K

Answer 1

Answer:

B

Explanation:

first break velocity into components

and at top vertical component is equal to zero.

and horizontal component remains unchanged.

and use formula

$ke = \frac{1}{2} m {v}^{2}$