Question

An object is projected at an angle of elivation of 45° with a velocity of 100 m/s. Calculate its range and time of flight

Answer 1

Given, θ=45°, u=100 m/s
Range = (u²sin2θ)/g = (100×100×sin90°)/10 = 10000/10=1000 m
Time of flight = (2usinθ)/g = (2×100×sin 45°)/10 = (√2×100)/10 = 10√2 s.

Answer 2

Let inclined angle = ∅
horizontal range = u²sin2∅/g
Here ,
u= 100 m/s
∅ = 45°
Range = (100)²sin2×45°/10
= (10)² sin90°/10
= 1000 m

Time of flight = 2usin∅/g
= 2 × 100 × sin45°/10
= 20× 1/√2
= 10√2 sec