Question

the length of the side of 1 square exceeds the length of the side of the Other square by 6 centimetre if the sum of the areas of two squares is 666 CM square then find the length of the sides of the squares

Answer 1

let the length of square be x
then length of another is x + 6
(x)^2 + (x + 6)^2 = 666
x^2 + x^2 + 36 + 12x = 666
2x^2 + 12x + 36 = 666
dividing eqn by 2
x^2 + 6x + 18 - 333 = 0
x^2 + 6x - 315 = 0
x^2 + 21x - 15x -315 = 0
x(x+21) -15(x+21)=0
so x=15
hence the length one 1 □ is 15
and of another is 21

Answer 2

See the attach file for ur ans