Question

an object is projected from ground with speed 20m/s at angle 30 with horizontal. its centripetal acceleration one second after the projection is (g=10m/s2)

Answer 1

hello mate !!

Please find below the solution to the asked query:

Given that the initial velocity of the particle is 20 m/s and the angle of projection is 300. Let the velocity of the object after t = 1 secis v. Therefore,

v cos α=u cos θ⇒v cos α=20 cos 30⇒v cos α=103√∴v sin α=v2−300−−−−−−−√&v sin α=u sin θ−gt⇒20 sin 30−10×1=v2−300−−−−−−−√⇒v2−300=0⇒v=103√ ms/

So, the particle will be at its highest point. Therefore the centripetal acceleration is g as shown in the figure below.

Answer 2

Answer:

Explanation:

Here is the answer :

10 m/s