Question

an object is projected from ground with speed 20m/s at angle 30° with horizontal. its centipetal acceleration one second after th projection is ​

Answer 1

First find angle after one second tantheta = 3/4 then find distance covered in x and y direction after 1 sec.

Then use y=xtantheta (1-x/R) to find radius of curvature after 1 sec.

And then use centripital acceleration =v^2/R