Question

an object is projected with a velocity of 20m/s making an angel 45° with the horizontal.the equation of the trajectory is y=Ax-bx^2 ,where y is height and x is horizontal distance.then A^2/4B is?​

Answer 1

a particle is projected with a velocity u m/s at an angle θ° with horizontal.then equation of trajectory is given by

here given, θ = 45° and u = 20 m/s and g = 10 m/s²

now compare it with y = Ax - Bx²

then, A = 1 and B = 1/40

so, A : B = 1 : 1/40 = 40 :1