Question

an object is projected with a velocity of 20m/s making an angle 45 with horizontal . The equation for trajectory is h=Ax-Bx^2 where h is height x is distance and A and B are constants . The ratio A:B is ?

Answer 1

if a particle is projected with a velocity u m/s at an angle θ° with horizontal.then equation of trajectory is given by $\bf{y = xtan\theta-\frac{gx^2}{2u^2cos^2\theta}}$

here given, θ = 45° and u = 20 m/s and g = 10 m/s²

$so, y = xtan45^{\circ}-\frac{gx^2}{2(20)^2cos^245^{\circ}}\\\\y=x-\frac{10x^2}{400}\\\\y=x-\frac{x^2}{40}$

now compare it with y = Ax - Bx²

then, A = 1 and B = 1/40

so, A : B = 1 : 1/40 = 40 : 1

Answer 2

Answer:

hope this will help you