Question

An object is projected with a velocity of 30 ms
at an angle of 60° with the horizontal. Determine the horizontal
range covered by the object.​

Answer 1

Explanation:

R=usin2theta/g

=30 x sin120/10 (g=10 m/s^2)

=3 x 2sin60cos60

=3 x 2 x \sqrt{3}/2 x 1/\sqrt{2} \\

=3 x \sqrt{3}/\sqrt{2} m

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