Question

An object is projected with velocity v. = 151 +20). Considering x along horizontal axis and
y along vertical axis. Find its velocity after 2 s.

Answer 1

☆Answer☆

An object is projected with velocity,

we can separate velocity in x and y - components

so,

we know, acceleration of projectile in horizontal line is zero. e.g.,

hence, velocity after 2 sec in horizontal direction.

similarly,

vertical direction , acceleration = -g[ negative sign shows acceleration acts vertically downward direction.]

now, velocity after 2 sect in vertical direction ,

hence , velocity after 2 sec ,

Answer 2

Answer:2

Explanation:

an object is projected with velocity,

we can separate velocity in x and y - components

so,

we know, acceleration of projectile in horizontal line is zero. e.g.,

hence, velocity after 2 sec in horizontal direction.

similarly,

vertical direction , acceleration = -g[ negative sign shows acceleration acts vertically downward direction.]

now, velocity after 2 sect in vertical direction ,

hence , velocity after 2 sec ,