An object is pushed along a horizontal surface in such a way that it starts with a velcity of 12m/s. its velocity decreases at a rate of 0.5m/s^2.find the time it will take to come to rest. z
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Here we have
initial velocity (u)= 12m/s
and final velocity (v)=0m/s (because the body comes to rest)
and acceleration (a)= –0.5m/s^2 (because the accl. is opposite to the direction of motion)
We know , v=u+at
=>0=12 + (–0.5)×t
=> t =–12/–0.5= 24
•°• It will come to rest after 24sec.
initial velocity (u)= 12m/s
and final velocity (v)=0m/s (because the body comes to rest)
and acceleration (a)= –0.5m/s^2 (because the accl. is opposite to the direction of motion)
We know , v=u+at
=>0=12 + (–0.5)×t
=> t =–12/–0.5= 24
•°• It will come to rest after 24sec.
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