An object is put in three liquids having different densities, one by one. The object floats with 1/9,2/11 and 3/7 parts of its volume outside the surface of liquids of densities d1. d2 and d3 respectively. Which of the following is the correct order of the densities of three liquids?
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Answer:
Explanation:
Buoyant Force is when a rigid object is submerged in a fluid (completely or partially), there exits an upward force on the object that is equal to the weight of the fluid that is displaced by the object.
In this case, there are 3 liquids with varying densities.
9
1
=0.11,
11
2
=0.18and
7
3
=0.43. These are the volume outside of liquids of densities d
1
,d
2
and d
e
respectively. This means that the buoyant force is maximum for d
3
and minimum for d
1
. As the buoyant force is proportional to density, the densities of the liquids are in the order d
1
<d
2
<d
3
.
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