Question

an object is released from a height of 20 meters what is the ratio of time taken in covering the first half of the distance to the time taken in covering the first half of the distance to the time taken in covering the second half the distance

Answer 1

Answer:

4×2^-2

Step-by-step explanation:

where h(t) is the height, g is gravity, v is initial velocity, and c is the original height. In this case:

h(8)=0=-4.9(8²)+0t+c

then:

4.9(64)=initial height=313.6

Then, the first 1/2 of the distance is 313.6/2, or 156.8. So:

4.9t²=156.8

t²=32

t=4√2