Question

An object is starting from rest, its velocity becomes 50m/s after 10 s. Calculate the displacement of the object?

Answer 1

Answer:

Here's your ans. BRUH!!

Given : U=0 m/s, v= 50m/s, t= 10 sec

From v= u + at then

a=(v-u)/t

a = 5m/s²

Also from v²= u² + 2aS

2500 = 0 + 2 x 5 × S

S= 250m.........

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Answer 2

Answer :

➥ The displacement of the object = 250 m

Given :

➤ Intial velocity of an object = 0 m/s

➤ Final velocity of an object (v) = 50 m/s

➤ Time taken (t) = 10 sec

To Find :

➤ Displacement if the object = ?

Solution :

First we need to calculate acceleration then we calculate the displacement of the object.

As we know that

$\tt{: \implies a = \dfrac{v - u}{t} }$

$\tt{: \implies a = \dfrac{50 - 0}{10} }$

$\tt{: \implies a = \dfrac{50}{10} }$

$\tt{: \implies \purple{ \underline{ \overline{ \boxed{ \green{ \bf{ \: \: a = 5\: m/s^2 \: \: }}}}}}}$

Now ,

We calculate displacement of the object.

From second equation of motion

$\tt{: \implies s = ut + \dfrac{1}{2} \times a {t}^{2} }$

$\tt{: \implies s = 0 \times 5 + \dfrac{1}{\cancel{\:2\:}} \times 5 \times \cancel{10} \times 10 }$

$\tt{: \implies s = 0 + 1 \times 5 \times 5 \times 10 }$

$\tt{: \implies s =0 + 5 \times 5 \times 10}$

$\tt{: \implies s =0 + 25 \times 10}$

$\tt{: \implies s =0 + 250}$

$\tt{: \implies \green{\underline{ \overline{ \boxed{ \purple{ \bf{ \: \: s = 250 \: m \: \: }}}}}}}$

Hence, the displacement of the object is 250 m.

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Some releted equations :

⪼ s = ut + ½ at²

⪼ v = u + at

⪼ v² = u² + 2as

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