Physics, asked by anyasingh86451, 1 year ago

An object is thrown up with a speed of 50 m/s.It's height from the ground after 7s is

Answers

Answered by jhubc

0

S = ut + 1/2at^2

= 50×7 + 1/2×10×49

= 350 + 245

= 595 m

Thus,height reached = 595 m

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