an object is thrown upward to a certain height with a velocity of 3 metre per second if the time required to reach the height is 5 second calculate the height at which it was thrown in Gravity 10 M per second used second equation of motion
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Given : velocity = 3m/s
distance= 5 seconds
v=0
v= u + at
0= 3 + ax5
therefore
a= -3/5
now, v²-u²= 2as
-9=-6/5s
s= 7.5m.
distance= 5 seconds
v=0
v= u + at
0= 3 + ax5
therefore
a= -3/5
now, v²-u²= 2as
-9=-6/5s
s= 7.5m.
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