An object is thrown upward to certain height the velocity of 3 metre per second if the time required to reach the height is 5 second calculate the height at which was thrown g equals to 10 m per second
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from second eq of motion
s=ut+1/2at2
s=3*5+1/2*(-10)*5*5
s=15+125=-110m
here negative sign shows the opposite direction of motion(against g)
s=ut+1/2at2
s=3*5+1/2*(-10)*5*5
s=15+125=-110m
here negative sign shows the opposite direction of motion(against g)
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