Question

when a substance having Mass 3 kg Rishu 600 CAL of heat is temperature increased by 10 degree Celsius what is the specific heat of the substance with full equation

Answer 1

mass, m = 3 kg

Heat, H = 600 cal

increase in temperature, ∆T = 10℃

specific heat capacity, C = ?

$H = mC \Delta T \\ \\ 600 = 3 \times C \times 10 \\ \\ C = \frac{600}{3 \times 10}\\ \\ C = 20\ cal \: {kg}^{-1} \: {{}^oC}^{-1}$

Answer 2

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mass, m = 3 kg

Heat, H = 600 cal

increase in temperature, ∆T = 10℃

specific heat capacity, C = ?

$H = mC \Delta T \\ \\ 600 = 3 \times C \times 10 \\ \\ C = \frac{600}{3 \times 10}\\ \\ C = 20\ cal \: {kg}^{-1} \: {{}^oC}^{-1}$

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