Question

An object is thrown upward to certain height with a velocity of 3 m/s . If the time requiredto reach the height is 5 sec calculate the height at which it was thrown

Answer 1

Given. initial velocity , u = 3 m/s

time taken , t = 5 sec.

WKT,

2nd equation of motion

s= ut + 1/2at ^ 2

so when

a = g = 9.8 m/s^2, s = h

then,

h = 3 × 5 + 1/2 × (9.8)× 5 ^ 2

h = 15 + 4.9 × 25

h = 15 + 122.5

h = 137.5 m