Question

An object is thrown upward with the speed of 10m/s from the height of 50m. Find the total height reached by the object

Answer 1

Answer:

Given :-

u = 10m/s

v = 0 m/s

h1 = 50 m

Total height (H) = ?

v^2 = u^2 - 2gh2

0^2 = 10^2 - 2 × 10 × h2

0 = 100 - 20 × h2

-100 = -20h2

h2 = 100/20

h2 = 5m

Total height = h1 + h2

= 50 + 5

= 55m

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Answer 2

Answer:

55m

Explanation:

u=10m/s. v=0m/s. H1=50m

total height=? !!

from the equation of motion

V2 square- u2 square=2gh2

0square-10square=2.10.h2

-100=20.h2

h2= 100/20

h2=5

total height =h1 + h2

50+5

55m

then the total height of the object is 55meters