an object is thrown upwards to a certain height with a velocity of 3 m/s. if the time required to reach the height is 5 sec. calculate the height at which it was thrown
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an object is thrown upward final velocity (v)=0
initial velocity (u)=3m/s
time (t)=5sec.
Height (s)=?
A.T.Q
Firstly,we find acceleration
a=v-u/t
a=0-3/5
a=-3/5
using second equation of motion
S=ut +1/2 ×a×t square
S=3×5+1/2×-3/5×5 square
S=15 -3/10×25
S=15 -15/2
S=30-15÷2
S=15/2
S=7.5m/s
Hope it will help you!
an object is thrown upward final velocity (v)=0
initial velocity (u)=3m/s
time (t)=5sec.
Height (s)=?
A.T.Q
Firstly,we find acceleration
a=v-u/t
a=0-3/5
a=-3/5
using second equation of motion
S=ut +1/2 ×a×t square
S=3×5+1/2×-3/5×5 square
S=15 -3/10×25
S=15 -15/2
S=30-15÷2
S=15/2
S=7.5m/s
Hope it will help you!
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