An object is thrown vertically up with a velocity 49m/'s. How high will it rise
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1
The answer may be approx 588.26 b coz hmax=u squared sin squared theta /2g
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2
=> v²-u²= 2as
=> (0) - (49)² = 2(-9.8)s
=> -2401 = -19.6s
=> s = 2401÷19.6
=> s = 122.5 metres
=> (0) - (49)² = 2(-9.8)s
=> -2401 = -19.6s
=> s = 2401÷19.6
=> s = 122.5 metres
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