Question

An object is thrown vertically up with velocity 'u' reaches maximum height in time 't'. The average velocity during this time is a) u/2 b) 2u/g c) ulg d) u? /4g​

Answer 1

Answer:

the correct option is (a) because average velocity is also equal to

$\frac{u + v}{2}$

where u in the initial velocity and v is the final velocity which is equal to zero when it reaches it's highest point.

So the correct answer is

$\frac{u}{2}$

PLEASE MARKS ME AS BRAINLIST