Question

An object is thrown vertically upward at 25.0 m/s. If it experiences an acceleration due to gravity of 9.8 m/s² [down], what is the object's velocity 3.0 s later?

Answer 1

Answer:

by netwon first equation

v = u + at

put all values u get ur answer

Answer 2

Given:

An object is thrown vertically upwards with an initial velocity of 25.0m/s

To Find:

The velocity of the object after 3.0s.

Solution:

Here in this problem, we will assume the upward direction of the motion to be positive.

The initial velocity of the object, $u=25.0m/s$

Acceleration due to gravity, $g=-9.8m/s^2$

Using the equation of uniformly accelerated motion,

$v=u+at$

  $=25.0-9.8(3.0)$

  $=-4.4m/s$

Hence, the velocity of the object after 3.0s is equal to 4.4m/s in the downward direction.