An object is thrown vertically upward from a speed of 19.6m/s if its mass is 500g, calculate its potential energy at highest point.
Answers
Answered by
2
m = 500g = 1/2 kg
u = 19.6 m/s
v = 0 at highest point
a = - g
s = H
V² - u² = 2as
- 19.6 × 19.6 = -2×9.8×H
H = 19.6 m
∆P.E = -Wc
Pf - Pi = -mgh
Pf = -1/2 × 9.8 × 19.6
Pf = -96.04 J
u = 19.6 m/s
v = 0 at highest point
a = - g
s = H
V² - u² = 2as
- 19.6 × 19.6 = -2×9.8×H
H = 19.6 m
∆P.E = -Wc
Pf - Pi = -mgh
Pf = -1/2 × 9.8 × 19.6
Pf = -96.04 J
surjitkumarsk:
What is pf and pi?
Please tell
pf = final P.E. ; pi = initial P.E
Wc = conservative force (gravitational Force)
Ok
We don't have definition of p.E of body we have only definition for change in p.E i.e Change in p.E = negative work done by conservative force
conservative forces :- which are only depends upon initial and final position i.e displacement not distance
Ok thanks
Similar questions