An object is thrown vertically upwards and
rises to a height of 45 m. Calculate
[Take, g = 10 m/s2] [3]
(a) The velocity with which the object was
thrown upward.
(b) The time taken by object to reach highest
point.
(c) Total time for which object remains in air
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Answer:
velocity is 30m/s and time taken to reach highest point is 3 secs and it remains 6 sec in air
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