Question

An object is thrown vertically upwards and rises to a height of 13.07m. Calculate
(i) the velocity with which the object was thrown upwards. (ii) the time taken by the object to reach the highest point. { take s=h(height) and a=g (acceleration due to gravity)} g=9.8m/s2​

Answer 1

Answer:

(i) To find Initial velocity (u)

we Will use, => v = u + gt

=> 0 = 16 +(- 9.8) t

=> 0+16 = -9.8t

=> 16/-9.8 = t

=> 1.63s = t

(ii) To find time ,

we will use => v²- u² = 2gs

Now put values,

=> (0)² - u² = 2*-9.8*13.07

=> u² = 256.172

=> u = √256.172

=> u = 16

Answer 2

Answer:

(1)v=u+at

0=16(-9.8)*t

0*16=-9.8*t

16/9.8=t

1.63=t